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return _tuple.__new__(_cls, ({arg_list}))
@classmethod
def _make(cls, iterable, new=tuple.__new__, len=len):
'Make a new {typename} object from a sequence or iterable'
result = new(cls, iterable)
if len(result) != {num_fields:d}:
raise TypeError('Expected {num_fields:d} arguments, got %d' % len(result))
return result
def __repr__(self):
'Return a nicely formatted representation string'
return '{typename}({repr_fmt})' % self
def _asdict(self):
'Return a new OrderedDict which maps field names to their values'
return OrderedDict(zip(self._fields, self))
def _replace(_self, **kwds):
'Return a new {typename} object replacing specified fields with new values'
result = _self._make(map(kwds.pop, {field_names!r}, _self))
if kwds:
raise ValueError('Got unexpected field names: %r' % kwds.keys())
return result
def __getnewargs__(self):
'Return self as a plain tuple. Used by copy and pickle.'
return tuple(self)
__dict__ = _property(_asdict)
def __getstate__(self):
'Exclude the OrderedDict from pickling'
pass
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'Point(x, y)'
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>>> p[0] + p[1] # indexable like a plain tuple
33
>>> x, y = p # unpack like a regular tuple
>>> x, y
(11, 22)
>>> p.x + p.y # fields also accessable by name
33
>>> d = p._asdict() # convert to a dictionary
>>> d['x']
11
>>> Point(**d) # convert from a dictionary
Point(x=11, y=22)
>>> p._replace(x=100) # _replace() is like str.replace() but targets named fields
Point(x=100, y=22)
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�Zd�Zd�ZRS(s�Dict subclass for counting hashable items. Sometimes called a bag
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>>> c.most_common(3) # three most common elements
[('a', 5), ('b', 4), ('c', 3)]
>>> sorted(c) # list all unique elements
['a', 'b', 'c', 'd', 'e']
>>> ''.join(sorted(c.elements())) # list elements with repetitions
'aaaaabbbbcccdde'
>>> sum(c.values()) # total of all counts
15
>>> c['a'] # count of letter 'a'
5
>>> for elem in 'shazam': # update counts from an iterable
... c[elem] += 1 # by adding 1 to each element's count
>>> c['a'] # now there are seven 'a'
7
>>> del c['b'] # remove all 'b'
>>> c['b'] # now there are zero 'b'
0
>>> d = Counter('simsalabim') # make another counter
>>> c.update(d) # add in the second counter
>>> c['a'] # now there are nine 'a'
9
>>> c.clear() # empty the counter
>>> c
Counter()
Note: If a count is set to zero or reduced to zero, it will remain
in the counter until the entry is deleted or the counter is cleared:
>>> c = Counter('aaabbc')
>>> c['b'] -= 2 # reduce the count of 'b' by two
>>> c.most_common() # 'b' is still in, but its count is zero
[('a', 3), ('c', 1), ('b', 0)]
cKs'tt|�j�|j||�dS(s Create a new, empty Counter object. And if given, count elements
from an input iterable. Or, initialize the count from another mapping
of elements to their counts.
>>> c = Counter() # a new, empty counter
>>> c = Counter('gallahad') # a new counter from an iterable
>>> c = Counter({'a': 4, 'b': 2}) # a new counter from a mapping
>>> c = Counter(a=4, b=2) # a new counter from keyword args
N(tsuperRRRY(RRGR((s!/sys/lib/python2.7/collections.pyR�scCsdS(s1The count of elements not in the Counter is zero.i((RR((s!/sys/lib/python2.7/collections.pyt__missing__�scCsP|dkr.t|j�dtd�dt�Stj||j�dtd��S(s�List the n most common elements and their counts from the most
common to the least. If n is None, then list all element counts.
>>> Counter('abcdeabcdabcaba').most_common(3)
[('a', 5), ('b', 4), ('c', 3)]
RitreverseN(RtsortedR2RoR[t_heapqtnlargest(Rtn((s!/sys/lib/python2.7/collections.pytmost_common�s "cCstjtt|j���S(s�Iterator over elements repeating each as many times as its count.
>>> c = Counter('ABCABC')
>>> sorted(c.elements())
['A', 'A', 'B', 'B', 'C', 'C']
# Knuth's example for prime factors of 1836: 2**2 * 3**3 * 17**1
>>> prime_factors = Counter({2: 2, 3: 3, 17: 1})
>>> product = 1
>>> for factor in prime_factors.elements(): # loop over factors
... product *= factor # and multiply them
>>> product
1836
Note, if an element's count has been set to zero or is a negative
number, elements() will ignore it.
(t_chaint
from_iterablet_starmapt_repeatR2(R((s!/sys/lib/python2.7/collections.pytelements�scCstd��dS([email protected]() is undefined. Use Counter(iterable) instead.(tNotImplementedError(RFRGtv((s!/sys/lib/python2.7/collections.pyRH�scKs�|dk r�t|t�rz|ra|j}xJ|j�D]#\}}||d�|||<q7Wq�tt|�j|�q�|j}x(|D]}||d�d||<q�Wn|r�|j|�ndS(s�Like dict.update() but add counts instead of replacing them.
Source can be an iterable, a dictionary, or another Counter instance.
>>> c = Counter('which')
>>> c.update('witch') # add elements from another iterable
>>> d = Counter('watch')
>>> c.update(d) # add elements from another counter
>>> c['h'] # four 'h' in which, witch, and watch
4
iiN(RRItMappingR�R2R�RRY(RRGRtself_gettelemtcount((s!/sys/lib/python2.7/collections.pyRY�s
cKs�|dk r�|j}t|t�r[x\|j�D]#\}}||d�|||<q1Wq�x(|D]}||d�d||<qbWn|r�|j|�ndS(s�Like dict.update() but subtracts counts instead of replacing them.
Counts can be reduced below zero. Both the inputs and outputs are
allowed to contain zero and negative counts.
Source can be an iterable, a dictionary, or another Counter instance.
>>> c = Counter('which')
>>> c.subtract('witch') # subtract elements from another iterable
>>> c.subtract(Counter('watch')) # subtract elements from another counter
>>> c['h'] # 2 in which, minus 1 in witch, minus 1 in watch
0
>>> c['w'] # 1 in which, minus 1 in witch, minus 1 in watch
-1
iiN(RR�RIR�R-tsubtract(RRGRR�R�R�((s!/sys/lib/python2.7/collections.pyR�s
cCs
|j|�S(sReturn a shallow copy.(R=(R((s!/sys/lib/python2.7/collections.pyRC6scCs|jt|�ffS(N(R=R)(R((s!/sys/lib/python2.7/collections.pyRE:scCs)||kr%tt|�j|�ndS(sGLike dict.__delitem__() but does not raise KeyError for missing values.N(R�RR$(RR�((s!/sys/lib/python2.7/collections.pyR$=scCsI|sd|jjSdjtdj|j���}d|jj|fS(Ns%s()s, s%r: %rs%s({%s})(R=R>R�Rvt__mod__R�(RR-((s!/sys/lib/python2.7/collections.pyRABs!cCs�t|t�stSt�}xA|j�D]3\}}|||}|dkr)|||<q)q)Wx?|j�D]1\}}||krm|dkrm|||<qmqmW|S(sAdd counts from two counters.
>>> Counter('abbb') + Counter('bcc')
Counter({'b': 4, 'c': 2, 'a': 1})
i(RIRtNotImplementedR-(RRNR6R�R�tnewcount((s!/sys/lib/python2.7/collections.pyt__add__Qs cCs�t|t�stSt�}xA|j�D]3\}}|||}|dkr)|||<q)q)WxC|j�D]5\}}||krm|dkrmd|||<qmqmW|S(s� Subtract count, but keep only results with positive counts.
>>> Counter('abbbc') - Counter('bccd')
Counter({'b': 2, 'a': 1})
i(RIRR�R-(RRNR6R�R�R�((s!/sys/lib/python2.7/collections.pyt__sub__ds cCs�t|t�stSt�}xU|j�D]G\}}||}||krQ|n|}|dkr)|||<q)q)Wx?|j�D]1\}}||kr�|dkr�|||<q�q�W|S(s�Union is the maximum of value in either of the input counters.
>>> Counter('abbb') | Counter('bcc')
Counter({'b': 3, 'c': 2, 'a': 1})
i(RIRR�R-(RRNR6R�R�tother_countR�((s!/sys/lib/python2.7/collections.pyt__or__ws
cCsxt|t�stSt�}xU|j�D]G\}}||}||krQ|n|}|dkr)|||<q)q)W|S(s� Intersection is the minimum of corresponding counts.
>>> Counter('abbb') & Counter('bcc')
Counter({'b': 1})
i(RIRR�R-(RRNR6R�R�R�R�((s!/sys/lib/python2.7/collections.pyt__and__�s
N(R>RVRWRRR�R�R�R\RHRYR�RCRER$RAR�R�R�R�(((s!/sys/lib/python2.7/collections.pyR�s"+
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